4(a+3)-5(a-1)=2

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Solution for 4(a+3)-5(a-1)=2 equation:


Simplifying
4(a + 3) + -5(a + -1) = 2

Reorder the terms:
4(3 + a) + -5(a + -1) = 2
(3 * 4 + a * 4) + -5(a + -1) = 2
(12 + 4a) + -5(a + -1) = 2

Reorder the terms:
12 + 4a + -5(-1 + a) = 2
12 + 4a + (-1 * -5 + a * -5) = 2
12 + 4a + (5 + -5a) = 2

Reorder the terms:
12 + 5 + 4a + -5a = 2

Combine like terms: 12 + 5 = 17
17 + 4a + -5a = 2

Combine like terms: 4a + -5a = -1a
17 + -1a = 2

Solving
17 + -1a = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-17' to each side of the equation.
17 + -17 + -1a = 2 + -17

Combine like terms: 17 + -17 = 0
0 + -1a = 2 + -17
-1a = 2 + -17

Combine like terms: 2 + -17 = -15
-1a = -15

Divide each side by '-1'.
a = 15

Simplifying
a = 15

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