4(a+3)-7=6a+21

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Solution for 4(a+3)-7=6a+21 equation: 



4(a+3)-7=6a+21

We move all terms to the left:

4(a+3)-7-(6a+21)=0

We multiply parentheses

4a-(6a+21)+12-7=0

We get rid of parentheses

4a-6a-21+12-7=0

We add all the numbers together, and all the variables

-2a-16=0

We move all terms containing a to the left, all other terms to the right

-2a=16

a=16/-2

a=-8

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