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4(a+3)=3(a+4)+2
We move all terms to the left:
4(a+3)-(3(a+4)+2)=0
We multiply parentheses
4a-(3(a+4)+2)+12=0
We calculate terms in parentheses: -(3(a+4)+2), so:We get rid of parentheses
3(a+4)+2
We multiply parentheses
3a+12+2
We add all the numbers together, and all the variables
3a+14
Back to the equation:
-(3a+14)
4a-3a-14+12=0
We add all the numbers together, and all the variables
a-2=0
We move all terms containing a to the left, all other terms to the right
a=2
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