4(a+3)=3(a+4)-9

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Solution for 4(a+3)=3(a+4)-9 equation: 



4(a+3)=3(a+4)-9

We move all terms to the left:

4(a+3)-(3(a+4)-9)=0

We multiply parentheses

4a-(3(a+4)-9)+12=0



We calculate terms in parentheses: -(3(a+4)-9), so:

3(a+4)-9

We multiply parentheses

3a+12-9

We add all the numbers together, and all the variables

3a+3

Back to the equation:

-(3a+3)



We get rid of parentheses

4a-3a-3+12=0

We add all the numbers together, and all the variables

a+9=0

We move all terms containing a to the left, all other terms to the right

a=-9

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