4(a+3)=4(4a+5)

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Solution for 4(a+3)=4(4a+5) equation:



4(a+3)=4(4a+5)
We move all terms to the left:
4(a+3)-(4(4a+5))=0
We multiply parentheses
4a-(4(4a+5))+12=0
We calculate terms in parentheses: -(4(4a+5)), so:
4(4a+5)
We multiply parentheses
16a+20
Back to the equation:
-(16a+20)
We get rid of parentheses
4a-16a-20+12=0
We add all the numbers together, and all the variables
-12a-8=0
We move all terms containing a to the left, all other terms to the right
-12a=8
a=8/-12
a=-2/3

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