4(a+3)=4(4a+5)

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Solution for 4(a+3)=4(4a+5) equation: 



4(a+3)=4(4a+5)

We move all terms to the left:

4(a+3)-(4(4a+5))=0

We multiply parentheses

4a-(4(4a+5))+12=0



We calculate terms in parentheses: -(4(4a+5)), so:

4(4a+5)

We multiply parentheses

16a+20

Back to the equation:

-(16a+20)



We get rid of parentheses

4a-16a-20+12=0

We add all the numbers together, and all the variables

-12a-8=0

We move all terms containing a to the left, all other terms to the right

-12a=8

a=8/-12

a=-2/3

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