4(a+4)-(2a+1)=2(3a+1)+1

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Solution for 4(a+4)-(2a+1)=2(3a+1)+1 equation: 



4(a+4)-(2a+1)=2(3a+1)+1

We move all terms to the left:

4(a+4)-(2a+1)-(2(3a+1)+1)=0

We multiply parentheses

4a-(2a+1)-(2(3a+1)+1)+16=0

We get rid of parentheses

4a-2a-(2(3a+1)+1)-1+16=0



We calculate terms in parentheses: -(2(3a+1)+1), so:

2(3a+1)+1

We multiply parentheses

6a+2+1

We add all the numbers together, and all the variables

6a+3

Back to the equation:

-(6a+3)



We add all the numbers together, and all the variables

2a-(6a+3)+15=0

We get rid of parentheses

2a-6a-3+15=0

We add all the numbers together, and all the variables

-4a+12=0

We move all terms containing a to the left, all other terms to the right

-4a=-12

a=-12/-4

a=+3

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