4(a+4)-(4+3a)=7a-(3+6a)

Solution for 4(a+4)-(4+3a)=7a-(3+6a) equation:

Simplifying
4(a + 4) + -1(4 + 3a) = 7a + -1(3 + 6a)

Reorder the terms:
4(4 + a) + -1(4 + 3a) = 7a + -1(3 + 6a)
(4 * 4 + a * 4) + -1(4 + 3a) = 7a + -1(3 + 6a)
(16 + 4a) + -1(4 + 3a) = 7a + -1(3 + 6a)
16 + 4a + (4 * -1 + 3a * -1) = 7a + -1(3 + 6a)
16 + 4a + (-4 + -3a) = 7a + -1(3 + 6a)

Reorder the terms:
16 + -4 + 4a + -3a = 7a + -1(3 + 6a)

Combine like terms: 16 + -4 = 12
12 + 4a + -3a = 7a + -1(3 + 6a)

Combine like terms: 4a + -3a = 1a
12 + 1a = 7a + -1(3 + 6a)
12 + 1a = 7a + (3 * -1 + 6a * -1)
12 + 1a = 7a + (-3 + -6a)

Reorder the terms:
12 + 1a = -3 + 7a + -6a

Combine like terms: 7a + -6a = 1a
12 + 1a = -3 + 1a

Add '-1a' to each side of the equation.
12 + 1a + -1a = -3 + 1a + -1a

Combine like terms: 1a + -1a = 0
12 + 0 = -3 + 1a + -1a
12 = -3 + 1a + -1a

Combine like terms: 1a + -1a = 0
12 = -3 + 0
12 = -3

Solving
12 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.