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4(a+4)=12+4a
We move all terms to the left:
4(a+4)-(12+4a)=0
We add all the numbers together, and all the variables
4(a+4)-(4a+12)=0
We multiply parentheses
4a-(4a+12)+16=0
We get rid of parentheses
4a-4a-12+16=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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