4(a+5)-5=3a-(6+a)

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Solution for 4(a+5)-5=3a-(6+a) equation: 



4(a+5)-5=3a-(6+a)

We move all terms to the left:

4(a+5)-5-(3a-(6+a))=0

We add all the numbers together, and all the variables

4(a+5)-(3a-(a+6))-5=0

We multiply parentheses

4a-(3a-(a+6))+20-5=0



We calculate terms in parentheses: -(3a-(a+6)), so:

3a-(a+6)

We get rid of parentheses

3a-a-6

We add all the numbers together, and all the variables

2a-6

Back to the equation:

-(2a-6)



We add all the numbers together, and all the variables

4a-(2a-6)+15=0

We get rid of parentheses

4a-2a+6+15=0

We add all the numbers together, and all the variables

2a+21=0

We move all terms containing a to the left, all other terms to the right

2a=-21

a=-21/2

a=-10+1/2

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