4(a+b)+3(b-a)=

Solution for 4(a+b)+3(b-a)= equation:

Simplifying
4(a + b) + 3(b + -1a) = 0
(a * 4 + b * 4) + 3(b + -1a) = 0
(4a + 4b) + 3(b + -1a) = 0

Reorder the terms:
4a + 4b + 3(-1a + b) = 0
4a + 4b + (-1a * 3 + b * 3) = 0
4a + 4b + (-3a + 3b) = 0

Reorder the terms:
4a + -3a + 4b + 3b = 0

Combine like terms: 4a + -3a = 1a
1a + 4b + 3b = 0

Combine like terms: 4b + 3b = 7b
1a + 7b = 0

Solving
1a + 7b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-7b' to each side of the equation.
1a + 7b + -7b = 0 + -7b

Combine like terms: 7b + -7b = 0
1a + 0 = 0 + -7b
1a = 0 + -7b
Remove the zero:
1a = -7b

Divide each side by '1'.
a = -7b

Simplifying
a = -7b