4(a-1)-10(a-3)=6(5a+15)

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Solution for 4(a-1)-10(a-3)=6(5a+15) equation: 



4(a-1)-10(a-3)=6(5a+15)

We move all terms to the left:

4(a-1)-10(a-3)-(6(5a+15))=0

We multiply parentheses

4a-10a-(6(5a+15))-4+30=0



We calculate terms in parentheses: -(6(5a+15)), so:

6(5a+15)

We multiply parentheses

30a+90

Back to the equation:

-(30a+90)



We add all the numbers together, and all the variables

-6a-(30a+90)+26=0

We get rid of parentheses

-6a-30a-90+26=0

We add all the numbers together, and all the variables

-36a-64=0

We move all terms containing a to the left, all other terms to the right

-36a=64

a=64/-36

a=-1+7/9

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