4(a-1)=5(a+3)

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Solution for 4(a-1)=5(a+3) equation:



4(a-1)=5(a+3)
We move all terms to the left:
4(a-1)-(5(a+3))=0
We multiply parentheses
4a-(5(a+3))-4=0
We calculate terms in parentheses: -(5(a+3)), so:
5(a+3)
We multiply parentheses
5a+15
Back to the equation:
-(5a+15)
We get rid of parentheses
4a-5a-15-4=0
We add all the numbers together, and all the variables
-1a-19=0
We move all terms containing a to the left, all other terms to the right
-a=19
a=19/-1
a=-19

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