4(a-12)=3b-23;2(a+b)=114

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Solution for 4(a-12)=3b-23;2(a+b)=114 system of equations: 


  • /| 4*(a-12)-(3*b)+23 = 0| 2*(a+b)-114 = 0
  • We try to solve the equation: 4*(a-12)-(3*b)+23 = 0
  • 4*(a-12)-3*b+23 = 0
  • 4*a-3*b-48+23 = 0
  • 4*a-3*b-25 = 0
  • 4*a-3*b-25 = 0 // - 4*a-25
  • -3*b = -(4*a-25) // : -3
  • b = (-(4*a-25))/(-3)
  • b = (25-(4*a))/(-3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*((25-(4*a))/(-3)+a)-114 = 0| b = (25-(4*a))/(-3)
  • 2*((25-4*a)/(-3)+a)-114 = 0
  • 14/3*a-392/3 = 0
  • 14/3*a-392/3 = 0 // + 392/3
  • 14/3*a = 392/3 // : 14/3
  • a = 392/3/14/3
  • a = 28
  • We insert the solution into one of the initial equations of our system of equations
  • For b = (25-(4*a))/(-3): 
  • b = (25-(4*28))/(-3)
  • b = (25-112)/(-3)
  • b = -87/(-3)
  • b = 29
  • We get a system of equations:
  • /| b = 29| a = 28

 

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