4(a-2)=10+a+3

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Solution for 4(a-2)=10+a+3 equation: 



4(a-2)=10+a+3

We move all terms to the left:

4(a-2)-(10+a+3)=0

We add all the numbers together, and all the variables

4(a-2)-(a+13)=0

We multiply parentheses

4a-(a+13)-8=0

We get rid of parentheses

4a-a-13-8=0

We add all the numbers together, and all the variables

3a-21=0

We move all terms containing a to the left, all other terms to the right

3a=21

a=21/3

a=7

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