4(a-3)-(4a+4)=3(5a+4)-13

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Solution for 4(a-3)-(4a+4)=3(5a+4)-13 equation: 



4(a-3)-(4a+4)=3(5a+4)-13

We move all terms to the left:

4(a-3)-(4a+4)-(3(5a+4)-13)=0

We multiply parentheses

4a-(4a+4)-(3(5a+4)-13)-12=0

We get rid of parentheses

4a-4a-(3(5a+4)-13)-4-12=0



We calculate terms in parentheses: -(3(5a+4)-13), so:

3(5a+4)-13

We multiply parentheses

15a+12-13

We add all the numbers together, and all the variables

15a-1

Back to the equation:

-(15a-1)



We add all the numbers together, and all the variables

-(15a-1)-16=0

We get rid of parentheses

-15a+1-16=0

We add all the numbers together, and all the variables

-15a-15=0

We move all terms containing a to the left, all other terms to the right

-15a=15

a=15/-15

a=-1

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