4(a-3)=8a-(4a-12)

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Solution for 4(a-3)=8a-(4a-12) equation:


Simplifying
4(a + -3) = 8a + -1(4a + -12)

Reorder the terms:
4(-3 + a) = 8a + -1(4a + -12)
(-3 * 4 + a * 4) = 8a + -1(4a + -12)
(-12 + 4a) = 8a + -1(4a + -12)

Reorder the terms:
-12 + 4a = 8a + -1(-12 + 4a)
-12 + 4a = 8a + (-12 * -1 + 4a * -1)
-12 + 4a = 8a + (12 + -4a)

Reorder the terms:
-12 + 4a = 12 + 8a + -4a

Combine like terms: 8a + -4a = 4a
-12 + 4a = 12 + 4a

Add '-4a' to each side of the equation.
-12 + 4a + -4a = 12 + 4a + -4a

Combine like terms: 4a + -4a = 0
-12 + 0 = 12 + 4a + -4a
-12 = 12 + 4a + -4a

Combine like terms: 4a + -4a = 0
-12 = 12 + 0
-12 = 12

Solving
-12 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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