4(a-5)+(4a-5)=2(4a-1)-29

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Solution for 4(a-5)+(4a-5)=2(4a-1)-29 equation:


Simplifying
4(a + -5) + (4a + -5) = 2(4a + -1) + -29

Reorder the terms:
4(-5 + a) + (4a + -5) = 2(4a + -1) + -29
(-5 * 4 + a * 4) + (4a + -5) = 2(4a + -1) + -29
(-20 + 4a) + (4a + -5) = 2(4a + -1) + -29

Reorder the terms:
-20 + 4a + (-5 + 4a) = 2(4a + -1) + -29

Remove parenthesis around (-5 + 4a)
-20 + 4a + -5 + 4a = 2(4a + -1) + -29

Reorder the terms:
-20 + -5 + 4a + 4a = 2(4a + -1) + -29

Combine like terms: -20 + -5 = -25
-25 + 4a + 4a = 2(4a + -1) + -29

Combine like terms: 4a + 4a = 8a
-25 + 8a = 2(4a + -1) + -29

Reorder the terms:
-25 + 8a = 2(-1 + 4a) + -29
-25 + 8a = (-1 * 2 + 4a * 2) + -29
-25 + 8a = (-2 + 8a) + -29

Reorder the terms:
-25 + 8a = -2 + -29 + 8a

Combine like terms: -2 + -29 = -31
-25 + 8a = -31 + 8a

Add '-8a' to each side of the equation.
-25 + 8a + -8a = -31 + 8a + -8a

Combine like terms: 8a + -8a = 0
-25 + 0 = -31 + 8a + -8a
-25 = -31 + 8a + -8a

Combine like terms: 8a + -8a = 0
-25 = -31 + 0
-25 = -31

Solving
-25 = -31

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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