4(a-5)+4a=3(a+4)

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Solution for 4(a-5)+4a=3(a+4) equation: 



4(a-5)+4a=3(a+4)

We move all terms to the left:

4(a-5)+4a-(3(a+4))=0

We add all the numbers together, and all the variables

4a+4(a-5)-(3(a+4))=0

We multiply parentheses

4a+4a-(3(a+4))-20=0



We calculate terms in parentheses: -(3(a+4)), so:

3(a+4)

We multiply parentheses

3a+12

Back to the equation:

-(3a+12)



We add all the numbers together, and all the variables

8a-(3a+12)-20=0

We get rid of parentheses

8a-3a-12-20=0

We add all the numbers together, and all the variables

5a-32=0

We move all terms containing a to the left, all other terms to the right

5a=32

a=32/5

a=6+2/5

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