4(a-7)+12=2(a-4)

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Solution for 4(a-7)+12=2(a-4) equation: 



4(a-7)+12=2(a-4)

We move all terms to the left:

4(a-7)+12-(2(a-4))=0

We multiply parentheses

4a-(2(a-4))-28+12=0



We calculate terms in parentheses: -(2(a-4)), so:

2(a-4)

We multiply parentheses

2a-8

Back to the equation:

-(2a-8)



We add all the numbers together, and all the variables

4a-(2a-8)-16=0

We get rid of parentheses

4a-2a+8-16=0

We add all the numbers together, and all the variables

2a-8=0

We move all terms containing a to the left, all other terms to the right

2a=8

a=8/2

a=4

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