4(a-7)+12=2(a-5)

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Solution for 4(a-7)+12=2(a-5) equation:


Simplifying
4(a + -7) + 12 = 2(a + -5)

Reorder the terms:
4(-7 + a) + 12 = 2(a + -5)
(-7 * 4 + a * 4) + 12 = 2(a + -5)
(-28 + 4a) + 12 = 2(a + -5)

Reorder the terms:
-28 + 12 + 4a = 2(a + -5)

Combine like terms: -28 + 12 = -16
-16 + 4a = 2(a + -5)

Reorder the terms:
-16 + 4a = 2(-5 + a)
-16 + 4a = (-5 * 2 + a * 2)
-16 + 4a = (-10 + 2a)

Solving
-16 + 4a = -10 + 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.
-16 + 4a + -2a = -10 + 2a + -2a

Combine like terms: 4a + -2a = 2a
-16 + 2a = -10 + 2a + -2a

Combine like terms: 2a + -2a = 0
-16 + 2a = -10 + 0
-16 + 2a = -10

Add '16' to each side of the equation.
-16 + 16 + 2a = -10 + 16

Combine like terms: -16 + 16 = 0
0 + 2a = -10 + 16
2a = -10 + 16

Combine like terms: -10 + 16 = 6
2a = 6

Divide each side by '2'.
a = 3

Simplifying
a = 3

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