4(a-8)+12=2(a-5)

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Solution for 4(a-8)+12=2(a-5) equation: 


Simplifying
4(a + -8) + 12 = 2(a + -5)

Reorder the terms:
4(-8 + a) + 12 = 2(a + -5)
(-8 * 4 + a * 4) + 12 = 2(a + -5)
(-32 + 4a) + 12 = 2(a + -5)

Reorder the terms:
-32 + 12 + 4a = 2(a + -5)

Combine like terms: -32 + 12 = -20
-20 + 4a = 2(a + -5)

Reorder the terms:
-20 + 4a = 2(-5 + a)
-20 + 4a = (-5 * 2 + a * 2)
-20 + 4a = (-10 + 2a)

Solving
-20 + 4a = -10 + 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.
-20 + 4a + -2a = -10 + 2a + -2a

Combine like terms: 4a + -2a = 2a
-20 + 2a = -10 + 2a + -2a

Combine like terms: 2a + -2a = 0
-20 + 2a = -10 + 0
-20 + 2a = -10

Add '20' to each side of the equation.
-20 + 20 + 2a = -10 + 20

Combine like terms: -20 + 20 = 0
0 + 2a = -10 + 20
2a = -10 + 20

Combine like terms: -10 + 20 = 10
2a = 10

Divide each side by '2'.
a = 5

Simplifying
a = 5

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