4(a-8)+20=2(a-5)

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Solution for 4(a-8)+20=2(a-5) equation: 



4(a-8)+20=2(a-5)

We move all terms to the left:

4(a-8)+20-(2(a-5))=0

We multiply parentheses

4a-(2(a-5))-32+20=0



We calculate terms in parentheses: -(2(a-5)), so:

2(a-5)

We multiply parentheses

2a-10

Back to the equation:

-(2a-10)



We add all the numbers together, and all the variables

4a-(2a-10)-12=0

We get rid of parentheses

4a-2a+10-12=0

We add all the numbers together, and all the variables

2a-2=0

We move all terms containing a to the left, all other terms to the right

2a=2

a=2/2

a=1

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