4(b+1)+2(b+3)=10

Solution for 4(b+1)+2(b+3)=10 equation:

Simplifying
4(b + 1) + 2(b + 3) = 10

Reorder the terms:
4(1 + b) + 2(b + 3) = 10
(1 * 4 + b * 4) + 2(b + 3) = 10
(4 + 4b) + 2(b + 3) = 10

Reorder the terms:
4 + 4b + 2(3 + b) = 10
4 + 4b + (3 * 2 + b * 2) = 10
4 + 4b + (6 + 2b) = 10

Reorder the terms:
4 + 6 + 4b + 2b = 10

Combine like terms: 4 + 6 = 10
10 + 4b + 2b = 10

Combine like terms: 4b + 2b = 6b
10 + 6b = 10

Add '-10' to each side of the equation.
10 + -10 + 6b = 10 + -10

Combine like terms: 10 + -10 = 0
0 + 6b = 10 + -10
6b = 10 + -10

Combine like terms: 10 + -10 = 0
6b = 0

Solving
6b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '6'.
b = 0

Simplifying
b = 0