4(b+1)+2b=3(2b-1)

Solution for 4(b+1)+2b=3(2b-1) equation:

Simplifying
4(b + 1) + 2b = 3(2b + -1)

Reorder the terms:
4(1 + b) + 2b = 3(2b + -1)
(1 * 4 + b * 4) + 2b = 3(2b + -1)
(4 + 4b) + 2b = 3(2b + -1)

Combine like terms: 4b + 2b = 6b
4 + 6b = 3(2b + -1)

Reorder the terms:
4 + 6b = 3(-1 + 2b)
4 + 6b = (-1 * 3 + 2b * 3)
4 + 6b = (-3 + 6b)

Add '-6b' to each side of the equation.
4 + 6b + -6b = -3 + 6b + -6b

Combine like terms: 6b + -6b = 0
4 + 0 = -3 + 6b + -6b
4 = -3 + 6b + -6b

Combine like terms: 6b + -6b = 0
4 = -3 + 0
4 = -3

Solving
4 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.