4(b+1)+9=2(3b-4)+b

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Solution for 4(b+1)+9=2(3b-4)+b equation:


Simplifying
4(b + 1) + 9 = 2(3b + -4) + b

Reorder the terms:
4(1 + b) + 9 = 2(3b + -4) + b
(1 * 4 + b * 4) + 9 = 2(3b + -4) + b
(4 + 4b) + 9 = 2(3b + -4) + b

Reorder the terms:
4 + 9 + 4b = 2(3b + -4) + b

Combine like terms: 4 + 9 = 13
13 + 4b = 2(3b + -4) + b

Reorder the terms:
13 + 4b = 2(-4 + 3b) + b
13 + 4b = (-4 * 2 + 3b * 2) + b
13 + 4b = (-8 + 6b) + b

Combine like terms: 6b + b = 7b
13 + 4b = -8 + 7b

Solving
13 + 4b = -8 + 7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.
13 + 4b + -7b = -8 + 7b + -7b

Combine like terms: 4b + -7b = -3b
13 + -3b = -8 + 7b + -7b

Combine like terms: 7b + -7b = 0
13 + -3b = -8 + 0
13 + -3b = -8

Add '-13' to each side of the equation.
13 + -13 + -3b = -8 + -13

Combine like terms: 13 + -13 = 0
0 + -3b = -8 + -13
-3b = -8 + -13

Combine like terms: -8 + -13 = -21
-3b = -21

Divide each side by '-3'.
b = 7

Simplifying
b = 7

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