4(b+1)-5=4b-1

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Solution for 4(b+1)-5=4b-1 equation: 


Simplifying
4(b + 1) + -5 = 4b + -1

Reorder the terms:
4(1 + b) + -5 = 4b + -1
(1 * 4 + b * 4) + -5 = 4b + -1
(4 + 4b) + -5 = 4b + -1

Reorder the terms:
4 + -5 + 4b = 4b + -1

Combine like terms: 4 + -5 = -1
-1 + 4b = 4b + -1

Reorder the terms:
-1 + 4b = -1 + 4b

Add '1' to each side of the equation.
-1 + 1 + 4b = -1 + 1 + 4b

Combine like terms: -1 + 1 = 0
0 + 4b = -1 + 1 + 4b
4b = -1 + 1 + 4b

Combine like terms: -1 + 1 = 0
4b = 0 + 4b
4b = 4b

Add '-4b' to each side of the equation.
4b + -4b = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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