4(b+1)=2(b+2)

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Solution for 4(b+1)=2(b+2) equation:


Simplifying
4(b + 1) = 2(b + 2)

Reorder the terms:
4(1 + b) = 2(b + 2)
(1 * 4 + b * 4) = 2(b + 2)
(4 + 4b) = 2(b + 2)

Reorder the terms:
4 + 4b = 2(2 + b)
4 + 4b = (2 * 2 + b * 2)
4 + 4b = (4 + 2b)

Add '-4' to each side of the equation.
4 + -4 + 4b = 4 + -4 + 2b

Combine like terms: 4 + -4 = 0
0 + 4b = 4 + -4 + 2b
4b = 4 + -4 + 2b

Combine like terms: 4 + -4 = 0
4b = 0 + 2b
4b = 2b

Solving
4b = 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
4b + -2b = 2b + -2b

Combine like terms: 4b + -2b = 2b
2b = 2b + -2b

Combine like terms: 2b + -2b = 0
2b = 0

Divide each side by '2'.
b = 0

Simplifying
b = 0

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