4(b+1)=3(b+2)+5

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Solution for 4(b+1)=3(b+2)+5 equation: 



4(b+1)=3(b+2)+5

We move all terms to the left:

4(b+1)-(3(b+2)+5)=0

We multiply parentheses

4b-(3(b+2)+5)+4=0



We calculate terms in parentheses: -(3(b+2)+5), so:

3(b+2)+5

We multiply parentheses

3b+6+5

We add all the numbers together, and all the variables

3b+11

Back to the equation:

-(3b+11)



We get rid of parentheses

4b-3b-11+4=0

We add all the numbers together, and all the variables

b-7=0

We move all terms containing b to the left, all other terms to the right

b=7

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