4(b+1)=3(b-1)

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Solution for 4(b+1)=3(b-1) equation: 



4(b+1)=3(b-1)

We move all terms to the left:

4(b+1)-(3(b-1))=0

We multiply parentheses

4b-(3(b-1))+4=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

4b-3b+3+4=0

We add all the numbers together, and all the variables

b+7=0

We move all terms containing b to the left, all other terms to the right

b=-7

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