4(b+1)=4b+4

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Solution for 4(b+1)=4b+4 equation:


Simplifying
4(b + 1) = 4b + 4

Reorder the terms:
4(1 + b) = 4b + 4
(1 * 4 + b * 4) = 4b + 4
(4 + 4b) = 4b + 4

Reorder the terms:
4 + 4b = 4 + 4b

Add '-4' to each side of the equation.
4 + -4 + 4b = 4 + -4 + 4b

Combine like terms: 4 + -4 = 0
0 + 4b = 4 + -4 + 4b
4b = 4 + -4 + 4b

Combine like terms: 4 + -4 = 0
4b = 0 + 4b
4b = 4b

Add '-4b' to each side of the equation.
4b + -4b = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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