4(b+12)=72

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Solution for 4(b+12)=72 equation: 



4(b+12)=72

We move all terms to the left:

4(b+12)-(72)=0

We multiply parentheses

4b+48-72=0

We add all the numbers together, and all the variables

4b-24=0

We move all terms containing b to the left, all other terms to the right

4b=24

b=24/4

b=6

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