4(b+3)+4=2b-3(b-2)

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Solution for 4(b+3)+4=2b-3(b-2) equation: 



4(b+3)+4=2b-3(b-2)

We move all terms to the left:

4(b+3)+4-(2b-3(b-2))=0

We multiply parentheses

4b-(2b-3(b-2))+12+4=0



We calculate terms in parentheses: -(2b-3(b-2)), so:

2b-3(b-2)

We multiply parentheses

2b-3b+6

We add all the numbers together, and all the variables

-1b+6

Back to the equation:

-(-1b+6)



We add all the numbers together, and all the variables

4b-(-1b+6)+16=0

We get rid of parentheses

4b+1b-6+16=0

We add all the numbers together, and all the variables

5b+10=0

We move all terms containing b to the left, all other terms to the right

5b=-10

b=-10/5

b=-2

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