4(b+3)=2(b-3)

Solution for 4(b+3)=2(b-3) equation:

Simplifying
4(b + 3) = 2(b + -3)

Reorder the terms:
4(3 + b) = 2(b + -3)
(3 * 4 + b * 4) = 2(b + -3)
(12 + 4b) = 2(b + -3)

Reorder the terms:
12 + 4b = 2(-3 + b)
12 + 4b = (-3 * 2 + b * 2)
12 + 4b = (-6 + 2b)

Solving
12 + 4b = -6 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
12 + 4b + -2b = -6 + 2b + -2b

Combine like terms: 4b + -2b = 2b
12 + 2b = -6 + 2b + -2b

Combine like terms: 2b + -2b = 0
12 + 2b = -6 + 0
12 + 2b = -6

Add '-12' to each side of the equation.
12 + -12 + 2b = -6 + -12

Combine like terms: 12 + -12 = 0
0 + 2b = -6 + -12
2b = -6 + -12

Combine like terms: -6 + -12 = -18
2b = -18

Divide each side by '2'.
b = -9

Simplifying
b = -9