4(b+3)=40

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Solution for 4(b+3)=40 equation: 



4(b+3)=40

We move all terms to the left:

4(b+3)-(40)=0

We multiply parentheses

4b+12-40=0

We add all the numbers together, and all the variables

4b-28=0

We move all terms containing b to the left, all other terms to the right

4b=28

b=28/4

b=7

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