4(b+4)+b=4(b-3)-1

Solution for 4(b+4)+b=4(b-3)-1 equation:

4(b+4)+b=4(b-3)-1

We move all terms to the left:

4(b+4)+b-(4(b-3)-1)=0

We add all the numbers together, and all the variables

b+4(b+4)-(4(b-3)-1)=0

We multiply parentheses

b+4b-(4(b-3)-1)+16=0


We calculate terms in parentheses: -(4(b-3)-1), so:

4(b-3)-1

We multiply parentheses

4b-12-1

We add all the numbers together, and all the variables

4b-13

Back to the equation:

-(4b-13)


We add all the numbers together, and all the variables

5b-(4b-13)+16=0

We get rid of parentheses

5b-4b+13+16=0

We add all the numbers together, and all the variables

b+29=0

We move all terms containing b to the left, all other terms to the right

b=-29