4(b+4)=19+4b

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Solution for 4(b+4)=19+4b equation:



4(b+4)=19+4b
We move all terms to the left:
4(b+4)-(19+4b)=0
We add all the numbers together, and all the variables
4(b+4)-(4b+19)=0
We multiply parentheses
4b-(4b+19)+16=0
We get rid of parentheses
4b-4b-19+16=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation

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