4(b+4)=2(3b+2)+2(b+1)

Solution for 4(b+4)=2(3b+2)+2(b+1) equation:

Simplifying
4(b + 4) = 2(3b + 2) + 2(b + 1)

Reorder the terms:
4(4 + b) = 2(3b + 2) + 2(b + 1)
(4 * 4 + b * 4) = 2(3b + 2) + 2(b + 1)
(16 + 4b) = 2(3b + 2) + 2(b + 1)

Reorder the terms:
16 + 4b = 2(2 + 3b) + 2(b + 1)
16 + 4b = (2 * 2 + 3b * 2) + 2(b + 1)
16 + 4b = (4 + 6b) + 2(b + 1)

Reorder the terms:
16 + 4b = 4 + 6b + 2(1 + b)
16 + 4b = 4 + 6b + (1 * 2 + b * 2)
16 + 4b = 4 + 6b + (2 + 2b)

Reorder the terms:
16 + 4b = 4 + 2 + 6b + 2b

Combine like terms: 4 + 2 = 6
16 + 4b = 6 + 6b + 2b

Combine like terms: 6b + 2b = 8b
16 + 4b = 6 + 8b

Solving
16 + 4b = 6 + 8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8b' to each side of the equation.
16 + 4b + -8b = 6 + 8b + -8b

Combine like terms: 4b + -8b = -4b
16 + -4b = 6 + 8b + -8b

Combine like terms: 8b + -8b = 0
16 + -4b = 6 + 0
16 + -4b = 6

Add '-16' to each side of the equation.
16 + -16 + -4b = 6 + -16

Combine like terms: 16 + -16 = 0
0 + -4b = 6 + -16
-4b = 6 + -16

Combine like terms: 6 + -16 = -10
-4b = -10

Divide each side by '-4'.
b = 2.5

Simplifying
b = 2.5