4(b+4)=80

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Solution for 4(b+4)=80 equation: 



4(b+4)=80

We move all terms to the left:

4(b+4)-(80)=0

We multiply parentheses

4b+16-80=0

We add all the numbers together, and all the variables

4b-64=0

We move all terms containing b to the left, all other terms to the right

4b=64

b=64/4

b=16

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