4(b+5)+18b=42

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Solution for 4(b+5)+18b=42 equation: 



4(b+5)+18b=42

We move all terms to the left:

4(b+5)+18b-(42)=0

We add all the numbers together, and all the variables

18b+4(b+5)-42=0

We multiply parentheses

18b+4b+20-42=0

We add all the numbers together, and all the variables

22b-22=0

We move all terms containing b to the left, all other terms to the right

22b=22

b=22/22

b=1

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