4(b+5)+3(2b+1)=

Solution for 4(b+5)+3(2b+1)= equation:

Simplifying
4(b + 5) + 3(2b + 1) = 0

Reorder the terms:
4(5 + b) + 3(2b + 1) = 0
(5 * 4 + b * 4) + 3(2b + 1) = 0
(20 + 4b) + 3(2b + 1) = 0

Reorder the terms:
20 + 4b + 3(1 + 2b) = 0
20 + 4b + (1 * 3 + 2b * 3) = 0
20 + 4b + (3 + 6b) = 0

Reorder the terms:
20 + 3 + 4b + 6b = 0

Combine like terms: 20 + 3 = 23
23 + 4b + 6b = 0

Combine like terms: 4b + 6b = 10b
23 + 10b = 0

Solving
23 + 10b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-23' to each side of the equation.
23 + -23 + 10b = 0 + -23

Combine like terms: 23 + -23 = 0
0 + 10b = 0 + -23
10b = 0 + -23

Combine like terms: 0 + -23 = -23
10b = -23

Divide each side by '10'.
b = -2.3

Simplifying
b = -2.3