4(b+5)+8(8b+1)=-40

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Solution for 4(b+5)+8(8b+1)=-40 equation: 



4(b+5)+8(8b+1)=-40

We move all terms to the left:

4(b+5)+8(8b+1)-(-40)=0

We add all the numbers together, and all the variables

4(b+5)+8(8b+1)+40=0

We multiply parentheses

4b+64b+20+8+40=0

We add all the numbers together, and all the variables

68b+68=0

We move all terms containing b to the left, all other terms to the right

68b=-68

b=-68/68

b=-1

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