4(b+5)-3(b-2)=17

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Solution for 4(b+5)-3(b-2)=17 equation: 



4(b+5)-3(b-2)=17

We move all terms to the left:

4(b+5)-3(b-2)-(17)=0

We multiply parentheses

4b-3b+20+6-17=0

We add all the numbers together, and all the variables

b+9=0

We move all terms containing b to the left, all other terms to the right

b=-9

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