4(b+5)=3b+35

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Solution for 4(b+5)=3b+35 equation:


Simplifying
4(b + 5) = 3b + 35

Reorder the terms:
4(5 + b) = 3b + 35
(5 * 4 + b * 4) = 3b + 35
(20 + 4b) = 3b + 35

Reorder the terms:
20 + 4b = 35 + 3b

Solving
20 + 4b = 35 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
20 + 4b + -3b = 35 + 3b + -3b

Combine like terms: 4b + -3b = 1b
20 + 1b = 35 + 3b + -3b

Combine like terms: 3b + -3b = 0
20 + 1b = 35 + 0
20 + 1b = 35

Add '-20' to each side of the equation.
20 + -20 + 1b = 35 + -20

Combine like terms: 20 + -20 = 0
0 + 1b = 35 + -20
1b = 35 + -20

Combine like terms: 35 + -20 = 15
1b = 15

Divide each side by '1'.
b = 15

Simplifying
b = 15

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