4(b+9)=2(b+72)

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Solution for 4(b+9)=2(b+72) equation: 



4(b+9)=2(b+72)

We move all terms to the left:

4(b+9)-(2(b+72))=0

We multiply parentheses

4b-(2(b+72))+36=0



We calculate terms in parentheses: -(2(b+72)), so:

2(b+72)

We multiply parentheses

2b+144

Back to the equation:

-(2b+144)



We get rid of parentheses

4b-2b-144+36=0

We add all the numbers together, and all the variables

2b-108=0

We move all terms containing b to the left, all other terms to the right

2b=108

b=108/2

b=54

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