4(b-1)+5(b+1)=100

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Solution for 4(b-1)+5(b+1)=100 equation: 



4(b-1)+5(b+1)=100

We move all terms to the left:

4(b-1)+5(b+1)-(100)=0

We multiply parentheses

4b+5b-4+5-100=0

We add all the numbers together, and all the variables

9b-99=0

We move all terms containing b to the left, all other terms to the right

9b=99

b=99/9

b=11

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