4(b-1)-3=-(b+3)+1

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Solution for 4(b-1)-3=-(b+3)+1 equation: 



4(b-1)-3=-(b+3)+1

We move all terms to the left:

4(b-1)-3-(-(b+3)+1)=0

We multiply parentheses

4b-(-(b+3)+1)-4-3=0



We calculate terms in parentheses: -(-(b+3)+1), so:

-(b+3)+1

We get rid of parentheses

-b-3+1

We add all the numbers together, and all the variables

-1b-2

Back to the equation:

-(-1b-2)



We add all the numbers together, and all the variables

4b-(-1b-2)-7=0

We get rid of parentheses

4b+1b+2-7=0

We add all the numbers together, and all the variables

5b-5=0

We move all terms containing b to the left, all other terms to the right

5b=5

b=5/5

b=1

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