4(b-1)-5(b+1)=0

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Solution for 4(b-1)-5(b+1)=0 equation:


Simplifying
4(b + -1) + -5(b + 1) = 0

Reorder the terms:
4(-1 + b) + -5(b + 1) = 0
(-1 * 4 + b * 4) + -5(b + 1) = 0
(-4 + 4b) + -5(b + 1) = 0

Reorder the terms:
-4 + 4b + -5(1 + b) = 0
-4 + 4b + (1 * -5 + b * -5) = 0
-4 + 4b + (-5 + -5b) = 0

Reorder the terms:
-4 + -5 + 4b + -5b = 0

Combine like terms: -4 + -5 = -9
-9 + 4b + -5b = 0

Combine like terms: 4b + -5b = -1b
-9 + -1b = 0

Solving
-9 + -1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + -1b = 0 + 9

Combine like terms: -9 + 9 = 0
0 + -1b = 0 + 9
-1b = 0 + 9

Combine like terms: 0 + 9 = 9
-1b = 9

Divide each side by '-1'.
b = -9

Simplifying
b = -9

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