4(b-2)=(2-b)

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Solution for 4(b-2)=(2-b) equation: 



4(b-2)=(2-b)

We move all terms to the left:

4(b-2)-((2-b))=0

We add all the numbers together, and all the variables

4(b-2)-((-1b+2))=0

We multiply parentheses

4b-((-1b+2))-8=0



We calculate terms in parentheses: -((-1b+2)), so:

(-1b+2)

We get rid of parentheses

-1b+2

Back to the equation:

-(-1b+2)



We get rid of parentheses

4b+1b-2-8=0

We add all the numbers together, and all the variables

5b-10=0

We move all terms containing b to the left, all other terms to the right

5b=10

b=10/5

b=2

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