4(b-2)=(2b-5)

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Solution for 4(b-2)=(2b-5) equation: 



4(b-2)=(2b-5)

We move all terms to the left:

4(b-2)-((2b-5))=0

We multiply parentheses

4b-((2b-5))-8=0



We calculate terms in parentheses: -((2b-5)), so:

(2b-5)

We get rid of parentheses

2b-5

Back to the equation:

-(2b-5)



We get rid of parentheses

4b-2b+5-8=0

We add all the numbers together, and all the variables

2b-3=0

We move all terms containing b to the left, all other terms to the right

2b=3

b=3/2

b=1+1/2

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