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4(b-2)=(2b-5)
We move all terms to the left:
4(b-2)-((2b-5))=0
We multiply parentheses
4b-((2b-5))-8=0
We calculate terms in parentheses: -((2b-5)), so:We get rid of parentheses
(2b-5)
We get rid of parentheses
2b-5
Back to the equation:
-(2b-5)
4b-2b+5-8=0
We add all the numbers together, and all the variables
2b-3=0
We move all terms containing b to the left, all other terms to the right
2b=3
b=3/2
b=1+1/2
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