4(b-2)=3(b-4+6

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Solution for 4(b-2)=3(b-4+6 equation: 



4(b-2)=3(b-4+6

We move all terms to the left:

4(b-2)-(3(b-4+6)=0

We add all the numbers together, and all the variables

4(b-2)-(3(b+2)=0

We multiply parentheses

4b-(3(b+2)-8=0

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